y=-(x-2)

y=3

方程式$|x-2|=3$の解を，
グラフの交点から確認してみましょう．

y=+(x-2)

x-2=3

-(x-2)=3

f(x) = abs(x - 2)
A = Intersect(f, a, (-1, 3))
B = Intersect(f, a, (5, 3))
C = Point(xAxis)
b = Segment(A, C)
D = Point(xAxis)
c = Segment(B, D)
g(x) = -abs(x - 2) - 0.019999999999999962
E = (-2, 2)
F = (-1.18, 2.74)
u = Vector(E, F)
G = (6, 2)
H = (5.24, 2.76)
v = Vector(G, H)